2y^2-32=-32

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Solution for 2y^2-32=-32 equation: 


Simplifying
2y2 + -32 = -32

Reorder the terms:
-32 + 2y2 = -32

Add '32' to each side of the equation.
-32 + 32 + 2y2 = -32 + 32

Combine like terms: -32 + 32 = 0
0 + 2y2 = -32 + 32
2y2 = -32 + 32

Combine like terms: -32 + 32 = 0
2y2 = 0

Solving
2y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '2'.
y2 = 0

Simplifying
y2 = 0

Take the square root of each side:
y = {0}

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